how to integrate (3x+4)^2
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(3x+4)² = [3x]² +16 + 24x
= 9x² + 24x +16
= 3x(3x+4)+4(3x+4). As, 24x = 12x +12x
= (3x+4)(3x+4)
x= -4/3,-4/3.
Hope this will help you.
= 9x² + 24x +16
= 3x(3x+4)+4(3x+4). As, 24x = 12x +12x
= (3x+4)(3x+4)
x= -4/3,-4/3.
Hope this will help you.
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i asked to integrate it
not to find the value of x
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