Question

how to intergrate e^ 2x+1 dx

Answer 1

Answer:

e^2x+1

Step-by-step explanation:

Because integration of e^a is always the same e^a

Answer 2

$HEYA \: \\ \\ integration \: of \: e {}^{2x + 1} \: dx \\ \\ put \: \: 2x + 1 = z \\ Differentiate \: \: both \: sides \: w.r.t \: x \: we \: have \\ \\ 2 = dz \div dx \\ \\ dx = dz \div 2 \\ \\ integration \: of \: \: \:( e {}^{z} dz) \times (1 \div 2) \\ \\ e {}^{z} \times (1 \div 2) \\ \\ e {}^{2x + 1} \times (1 \div 2) \: + c \: \\ where \: c \: is \: called \: constant \: of \: integration \:$