Question

how to learn trigonometric ratios of 30 ,60 ,45, 90 and 0 pls tell easy way
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Answer 1

Answer:

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Step-by-step explanation:

First you should remember atleast sin theta and tan theta ratio values

then you can remember all trigonometric ratios

for sin 0 = 0

sin 30° = 1/2

sin 45° = 1/√2

sin 60° = √3/2

sin 90° = 1

then cos theta write in reverse from sin 90° to sin 0° = from cos 0° to cos 90°

that is cos 0 = 1

cos 30° = √3/2

cos 45° = 1/√2

cos 60° = 1/2

cos 90° = 0

then cosec theta = 1 / sin theta

that is

cosec 0° = 1/ sin 0° = 1/0 = 0

cosec 30° = 1 / sin 30° = 1/ (1/2) = 2

cosec 45° = 1 / sin 45° = 1 / (1/√2) = √2

cosec 60° = 1 / sin 60° = 1 / (√3/2) = 2/√3

cosec 90° = 1 / sin 90° = 1 / 1 = 1

then sec theta = 1 / cos theta = reverse of cosec theta

that is

sec 0° = 1

sec 30° = 2/√3

sec 45° = √2

sec 60° = 2

sec 90° = 0

then now remember the values of tan theta

tan 0° = 0

tan 30° = 1/√3

tan 45° = 1

tan 60° = √3

tan 90° = not defined

then cot theta = reverse of tan theta

cot 0° = not defined

cot 30° = √3

cot 45° = 1

cot 60° = 1/√3

cot 90° = 1