How to learn values of trigonometric angles with some sorta short-cut?
Answers
Answered by
1
learn value as
degrees: 0 30 45 60 90
sine root0/4 rt1/4 rt2/4 rt. 3/4 rt4/4
=0 =1/2 =1/rt 2 =rt3/2 =1
cosine 1 rt3/2 1/rt 2 1/2 0
cosine is just opposite of sine
and tan is sin/cos
so by this tan will be finded out
and cosec is inverse of sine
sec is inverse of cos
and cot is inverse of tan
degrees: 0 30 45 60 90
sine root0/4 rt1/4 rt2/4 rt. 3/4 rt4/4
=0 =1/2 =1/rt 2 =rt3/2 =1
cosine 1 rt3/2 1/rt 2 1/2 0
cosine is just opposite of sine
and tan is sin/cos
so by this tan will be finded out
and cosec is inverse of sine
sec is inverse of cos
and cot is inverse of tan
Answered by
0
as we that the formula LAL÷KKA
and for using this tricky formula be measure the order of trigonometric angles as I say that sin theta cos theta tan theta cot theta sec theta cosec theta
sin theta is equal to L÷K
COS=A÷K
TAN=L÷A
COT =A÷L
SEC=K÷A
COSEC=K÷L
and for using this tricky formula be measure the order of trigonometric angles as I say that sin theta cos theta tan theta cot theta sec theta cosec theta
sin theta is equal to L÷K
COS=A÷K
TAN=L÷A
COT =A÷L
SEC=K÷A
COSEC=K÷L
SanjeevKumarmeena:
koi nhi maine ye ker diya
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