Question

how to locate √5 on number line​

Answer 1

❏ Step 1: On the number line, take 2 units from O and represent the point as A.

❏ Step 2: At point A, draw a perpendicular and mark B such that AB = 1 unit.

❏ Step 3: Now, with O as the center and OB as radius, draw an arc to cut the number line at C.

❏ Step 4: Point C represents √5 on the number line.

Answer 2

$\huge⚘ \bf \ \red{Answer}$

$\red{Step \: 1:} On \: the \:  number \: line, \: take \: 2 \: units \: from \: O \: and \\ represent \: the \: point \: as \: A. \\\red{Step \: 2: }At \: point \: A, \: draw \: a  \: perpendicular  \: and \: mark \: B \\ such \: that \: AB = 1 \: unit. \\ \\ \red{Step \: 3: }Now, \: with \: O \: as \: the \: center \: and \: OB \: as  \: radius, \\ draw \: an \: arc \: to \: cut \: the \: number \: line \: at \: C. \\ \\ \red{Step 4: }Point  \: C  \: represents \: √5 \: on \: the \: number \: line. \\ \\ In \: △OAB, \: using \: Pythagoras \: theorem, \\ we \: have \\ OB² = OA² + AB² \\ = 2² + 1² \\ = 5 \\ ∴ OB = √5 units \\ Since, \: OB = OC = √5 units, \: therefore, \: point \: C \: represents  \: √5 \: on \: the \\ number \: line.</p><p>$