Question

How to make 45'angle

Answer 1

here is your answer dear
first construct 90°
then it's bisector....
see attachment

Answer 2

1). Use ruler and draw a Line segment OB of any convenient length.

 

2). Now use compass and open it to any convenient radius. And with O as center , draw an arc which cutsline segment OB at X .  



3). Again use compass and opened to the same radius (as of step 2). And with X as center , draw an arc which cuts first arc at D .



4). Again use compass and opened to the same radius (as of step 2). And with D as center , draw another arc which cuts first arc at C .  
 

5). Again use compass and opened to the same radius (as of step 2). And With C & D as center , draw two arcs which cuts each other at E .



6). Join OE and extent it to A .



7). Above formed angle AOB = 90 Degree 

Now, to construct at 45 degree angle, we will construct the angle bisector of above angle AOB. And its done in the following steps: 

8). Again use compass and open it to any convenient radius. And with O as center , draw an arc which cutsline segment OB at P and OA at Q .  



9) Again use compass and opened to same radius (as of step 8).And with P & Q as center and, draw two arcs which cuts each other at point F.

 

10) Join OF and extend to E. 



11) EO is the bisector of Angle AOB 
Therefore, Angle AOE = Angle EOB = ½ of Angle AOB = 45 Degree each

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