Question

How to make a draw an equilateral triangle whose each side of the 5cm

Answer 1

Step-by-step explanation:

Steps of construction:

Let ABC be the ∆:

(1)Draw AB as base = 5 cm.

(2) Draw perpendicular bisector of AB.

(3) Open the compass for 5 cm, keep the pointer at A and draw an arc such                 that it cuts the bisector.

(4) Do same with point B and wherever those arcs meet name that point C.

(5) Thus, ABC is the required ∆.

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