Question

how to make a square root spiral of √5.

Answer 1

Answer:

please mark me as brainliest

Answer 2

STEP - 1

Construct an isoceles rt.triangle ABC with side 1 inch.then its hypotenuse is equal to √5

STEP - 2

Construct a line perpendicular to segment AC. construct line segment CD on this new line segment.equal to the length of line segment AB and then join AD using pythagorus thm. the length of AD becomes √6

STEP - 3

Similarly construct a line perpendicular to D whose length is equal to 1 inch upto E.

now join AE. similarly using pythagorus theorm the length of AE becomes √25 = 5

STEP - 4

repeat these steps untill you have 11 right angles triangles.