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If the length of a rectangle is four times its width, and the perimeter of the rectangle is 70, what is its area?
Let the width of the rectangle is x units
Thus the length of the rectangle = 4x units
We know Perimeter = 2 (length + width)
Perimeter = 2 (4x + x)
Perimeter = 2 (5x)
Perimeter = 10x
10x = 70 units
10x = 70
x = 70/10
x = 7 units
Thus the width of the rectangle is 7 units
Length of the rectangle 4x = 4 × 7 = 28 units
Area of rectangle = length × width
Area of rectangle = 28 × 7 = 196 sq. units
Answer : the area of the rectangle is 196 sq. units
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