Question

How to measure the angle of resultant force?

Answer 1

Answer:

let be angle between two forces = beta

Your answer is in given picture

if you face any problem with solution then contact you

I think it's helpful for you

thanks #_brainly_mate

Pleazzz mark me as brainliest

Answer 2

Answer:

the magnitude equal to the sum of the two magnitudes:

• Two forces acting in opposite directions

Let's consider the case in which an object is subject to two forces that act in opposite directions.

If the two forces are equal in magnitude:

The resultant force will be zero because two opposite forces cancel each other out.

On the other hand, if the two forces are not equal in magnitude:

The resultant force will be in the same direction as the force with the larger magnitude (the 5 N force in the example), and have the magnitude equal to the difference between the magnitudes of the two forces (in the example that would be 2 N):

• More than 2 forces parallel to one another

Let's now consider the case in which an object is subject to more than two parallel forces:

To find the resultant force in this case, we first sum all the forces that go in one direction, and then all the forces that go in the other direction:

At this point, we have two forces that are in opposite directions, which is a case that we already know how to solve: the resultant force has the same direction as the force with the larger magnitude (the 11 N force), and its magnitude is equal to the difference between the two magnitudes (4 N):

• Two forces that are not parallel

In the previous cases, we have forces that are all parallel to one another. It's time to consider the case in which an object is subject to two forces that are not parallel.

For example, let's assume that we have a block subject to two forces, F1 and F2.

F1 has magnitude 50 N and is applied at a 45° angle, whereas F2 has magnitude 60 N and is applied horizontally, as shown in the free-body diagram below:

How do we find the resultant force R in this case?

The first step is to draw coordinate axes on our free-body diagram.

Since one of the two forces is horizontal, for convenience, we choose the x-axis horizontal, and the y-axis vertical, and we place the origin at the center of our block:

The next step is to determine the x and y components of all the forces that act on the block:

F1x = F1 cos 45°

F2x = F2

F1y = F1 sin 45°

F2y = 0

Now comes the important part:

If we sum all the x components, we will get the x component of the resultant force:

F1x + F2x = Rx

Rx = F1x + F2x

Rx = F1 cos 45° + F2

Rx = (50 N) (cos 45°) + 60 N

Rx = 95 N

Similarly, if we sum all the y components, we will get the y component of the resultant force:

F1y + F2y = Ry

Ry = F1y + F2y

Ry = F1 sin 45° + 0

Ry = F1 sin 45°

Ry = (50 N) (sin 45°)

Ry = 35 N

At this point, we know the x and y components of R, which we can use to find the magnitude and direction of R: