Chemistry, asked by viveka2, 1 year ago

How to name this?? Pls fastt

Attachments:

Anonymous: Prop-1-en-3-ol
viveka2: wont it be prop3enol
tasniahh: I too think it would be prop-3-en-1-ol
Anonymous: I wrote it wrong above.. it's Prop-2-en-1-ol
tasniahh: Since the functional group OH is higher in the chain than carbon-carbon double bond, we should count the carbon skeleton from the right side
tasniahh: oh yeah sorry , prop-2-en-1-ol
Anonymous: Yeah.. now u got it!
tasniahh: :)

Answers

Answered by Anonymous
0
Numbering from right , The IUPAC name is Prop-2-en-1-ol

viveka2: it is starting frm 3 so it can be prop 3 enol
viveka2: ??
Anonymous: We have to seperately give numberings for alkene and functional group (alcohol)
Anonymous: Yeah
Answered by Anonymous
0
It's IUPAC name will be
=> prop-2-en-1-ol
Or
=>
Or
2-propen-1-ol
Attachments:

Anonymous: Alkenes r also functional grps
Anonymous: But alcohol is given more preference than alkene
Anonymous: Yes
Anonymous: R u both in 11th?
Anonymous: No , I'm in 10th
Anonymous: Ok
Anonymous: Is that correct now?
Anonymous: Plz check
Anonymous: Yeah
Anonymous: ^_^
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