Question

How to obtain ph of solition by mixing stron strong base?

Answer 1

Let the “equal volume” under consideration be 1 L1 L.

The acid with pH=5pH=5 has [H+]=10−5 M[H+]=10−5 M. The acid with pH=3pH=3has [H+]=10−3 M[H+]=10−3 M.

When you add these two, you will have a total solution of volume 2 L2 L (assuming ideal solution) with (0.001+0.00001)=0.00101 mol H+(0.001+0.00001)=0.00101 mol H+.

So, the value of [H+][H+] is 0.00101 mol2 L=0.000505 M0.00101 mol2 L=0.000505 M.

So, the pHpH is −log100.000505≈3.297−log100.000505≈3.297.

MARK BRAINLIEST..