Question

How to predict the period and group of the element having outer electronic configuration 3s2 3p4 in the modern periodic table?

Answer 1

Answer:

Period number=3

Group number=16

Explanation:

We are given that outer electronic configuration of an element

$2s^23p^4$

We have to predict the period and the group of the element.

Number of Period=Maximum number of principle number

Group no of elements which configuration end with p- orbitals =12+number of electrons in P - orbital

Maximum principle number =3

Period number=3

Number of electrons in P- orbital =4

Group number=12+4=16