Question

how to prepare 0.5 n oxalic acid solution in250ml​

Answer 1

Explanation:

We know that the molar mass of oxalic acid is 90g. We also know that it is diprotic, having 2 H+ ions to donate in a reaction. Therefore, the Normality will be ½ the molarity. So, we need to add 5.625g of oxalic acid to water, and then add more water to make up 250ml of solution.

Answer 2

Dissolve 5.625 grams of oxalic acid and dissolve in 250ml​ of water

Explanation:

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Mathematically,

$\text{Normality of solution}=\frac{\text{Given mass}\times 1000}{\text{Equivalent mass}\times \text{Volume of solution (in mL)}}$

Mass of oxalic acid = x g

Equivalent mass of oxalic acid= $\frac{\text{Molecular mass}}{\text{Basicity}}=\frac{90}{2}=45g/eq$

Volume of solution = 250 mL

Putting values in above equation, we get:

$0.5=\frac{x\times 1000}{45g/eq\times 250mL}$

$x=5.625g$

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