Question

How to prepare 10% solution of potassium iodide?

Answer 1

Answer:

Dissolve 5 g of potassium iodide in 10 ml water. Mix the two solutions and add water to make 100 ml. Dissolve 2 g in 10 ml water. To 10 ml of this solution add 90 ml of water and 20 g of sodium bisulfite.

Answer 2

Dissolve 10 grams of KI in 100mL of water to preapre 10% solution of KI.

Step-by-step explanation:

Given: potssium iodide salt is given and distilled water is given.

To find: preparation of 10% KI solution.

Formula to be used: % m/V = $\frac{mass-of-solute}{volume-of-solution}*100$

Step 1 of 1

The mass of KI that is needed to prepare 10% solution of KI can be determined by using the mass by volume formula of percentage composition.

% m/V = $\frac{mass-of-solute}{volume-of-solution}*100$

Let the amount of water be taken is 100mL.

So, the amount of solute needed will be:

$10=\frac{x}{100} *100\\\\x=10gm$

Therefore, 10 grams of KI will be dissolved in 100 mL of water to obtain 10% solution of KI.