Chemistry, asked by Rajpoot1407, 1 year ago

How to prepare 100 ml of 0.025n sodium thiosulfate?

Answers

Answered by danielochich
11
Sodium thiosulfate usually exist as Na2S2O3·5H2O

with a molar mass of 248g/mol

This mass contains 158g of sodium thiosulfate

100ml of 0.025M Sodium thiosulfate will contain = 100/1000 x 0.025 = 0.0025 moles of the thiosulfate.

This has a mass of = 0.0025 x 158 = 0.395 ≈ 0.4g of sodium thiosulfate


if 158g is contained in 248g of hydrated salt

∴ 0.4g = ( 0.4 x 248)/158 = 0.6g

PREPARATION
1. Measure 0.6g of hydrated sodium thiosulfate using electric balance and add it in to a 100ml volumetric flask

2. Add some distilled water, about 30ml or so

3. Shake well for the sodium thiosulfate to dissolve

4. Add more water and shake

5. Finally, let the flask stand and add water little at a time carefully until it reaches the 100ml mark

This will be a 0.025M sodium thiosulfate solution



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