How to prepare 100ml of 0.1n silver nitrate solution?
Answers
Answered by
2
hii dear here ur answer...
Simple, use n1 v1=n2 v2 rulen1= 0.1V1= x mLV2= say 100 mLn2= 0.02
Therefore x = 100 x 0.02/0.1 = 20mL
Therefore 20 mL of 0.1N diluted to 100 mL solvent gives 0.02N Silver nitrate.....###hope help u
Simple, use n1 v1=n2 v2 rulen1= 0.1V1= x mLV2= say 100 mLn2= 0.02
Therefore x = 100 x 0.02/0.1 = 20mL
Therefore 20 mL of 0.1N diluted to 100 mL solvent gives 0.02N Silver nitrate.....###hope help u
Similar questions