Chemistry, asked by vediiika5233, 1 year ago

How to prepare 100ml of 0.1n silver nitrate solution?

Answers

Answered by Anonymous
2
hii dear here ur answer...

Simple, use n1 v1=n2 v2 rulen1= 0.1V1= x mLV2= say 100 mLn2= 0.02

Therefore x = 100 x 0.02/0.1 = 20mL

Therefore 20 mL of 0.1N diluted to 100 mL solvent gives 0.02N Silver nitrate.....###hope help u
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