Chemistry, asked by Pjasmine009, 2 months ago

How to prepare phosphonitrilic halid

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Answered by manishathakur10588
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Explanation:

Phosphonitrilic halide polymers - Ethyl Corporation. Abstract: Halophosphazene polymers such as linear phosphonitrilic chloride polymers are prepared in two stages by (i) heating a nitrogen source (e.g., NH3 ; NH4 Cl; etc.) with an excess of a phosphorus source (e.g., PCl5 ; PCl3 +Cl2 ; P+Cl2 .

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Answered by asadbinabbas96
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Answer:

Abstract

The reaction between phosphorus pentachloride and phosphonitrilic chloride trimer and tetramer, under controlled conditions, was shown to yield the linear phosphonitrilic chlorides [Cl(PCl2N)nPCl3]PCl6 where n equals 3 and 4, respectively. A mechanism is proposed involving a complex between the PCl4+ cation and the cyclic phosphonitrile through a ring nitrogen atom. Evidence, based on phosphorus NMR, indicates that the next step in the reaction between the linear chloride, [Cl(PCl2N)3PCl3]PCl6, and additional (PNCl2)3 leads to the compound [Cl(PCl2N)6·PCl3] PCl6, probably by a similar mechanism. The derivatives, [Cl(PCl2N)3PCl3][MCl(v+1)], where M = boron and aluminum, were prepared and found to be fluids. The tetrachloroaluminate is thermally stable to 700°C and, although no change in physical appearance was observed, phosphorus NMR indicated that a mixture of species of the type [Cl(PCl2N)nPCl3]AlCl4 was present. At elevated temperatures, the tetrachloroborate derivative, [Cl(PCl2N)3PCl3]BCl4, underwent a similar cationic rearrangement, although it was also accompanied by the elimination of PCl4BCl4 and formation of phosphonitrilic chloride rubbery polymer.

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