Question

how to proof derevation 2nd Equation of Motion?

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Answer 1

Answer:

Velocity is defined as the rate of change of displacement. This is mathematically represented as:

Velocity=Displacement/Time

Rearranging, we get

Displacement=Velcoity×Time

If the velocity is not constant then in the above equation we can use average velocity in the place of velocity and rewrite the equation as follows:

Displacement=((InitialVelocity+FinalVelocity)/2)×Time

Substituting the above equations with the notations used in the derivation of the first equation of motion, we get

s=(u+v)/2×t

From the first equation of motion, we know that v = u + at. Putting this value of v in the above equation, we get

s=u+(u+at))/2×t

s=(2u+at)/2×t

s=(2u/2+at/2)×t

s=(u+(1at)/2)×t

On further simplification, the equation becomes:

s=ut+1/2at^2

Explanation:

Answer 2

There are three equations of motion that can be used to derive components such as displacement(s), velocity (initial and final), time(t) and acceleration(a). The following are the three equation of motion: First Equation of Motion : v=u+at. Second Equation of Motion : s=ut+12at2.