how to prove 2+root3 is irrational number
Answers
Answered by
852
Hi friend,
Let 2+√3 is a rational number.
A rational number can be written in the form of p/q.
2+√3=p/q
√3=p/q-2
√3=(p-2q)/q
p,q are integers then (p-2q)/q is a rational number.
But this contradicts the fact that √3 is an irrational number.
So,our supposition is false.
Therefore,2+√3 is an irrational number.
Hence proved.
Hope it helps
Let 2+√3 is a rational number.
A rational number can be written in the form of p/q.
2+√3=p/q
√3=p/q-2
√3=(p-2q)/q
p,q are integers then (p-2q)/q is a rational number.
But this contradicts the fact that √3 is an irrational number.
So,our supposition is false.
Therefore,2+√3 is an irrational number.
Hence proved.
Hope it helps
akash92:
pls help in my question
Answered by
297
Hey there !
Let us assume that :-
2 + √3 is a rational number.
Let , 2 + √3 = r , where "r" is a rational number
Squaring both sides ,
[2 + √3 ]² = r²
2² + 2 x 2 x √3 + [√3]² = r²
4 + 4√3 + 3 = r²
7 + 4√3 = r²
4√3 = r² - 7
√3 = r² - 7÷ 4
So ,
we see that LHS is purely irrational.
But , on the other side , RHS is rational.
This contradicts the fact that 2+√3 is rational.
Hence , our assumption was wrong.
Hence ,
2+√3 is a irrational no:
Let us assume that :-
2 + √3 is a rational number.
Let , 2 + √3 = r , where "r" is a rational number
Squaring both sides ,
[2 + √3 ]² = r²
2² + 2 x 2 x √3 + [√3]² = r²
4 + 4√3 + 3 = r²
7 + 4√3 = r²
4√3 = r² - 7
√3 = r² - 7÷ 4
So ,
we see that LHS is purely irrational.
But , on the other side , RHS is rational.
This contradicts the fact that 2+√3 is rational.
Hence , our assumption was wrong.
Hence ,
2+√3 is a irrational no:
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