how to prove √6 irrational
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- let suppose √ 6 is rational no.
- then it write in p/q form .
- (co-prime and q not equal to 0)
- squaring on both side.
- 1/6=p2/q2
- p2=6q2___1eq
- 6is a factor of p2
- hence 2is a factor of p
- let p=6x
- substituting in 1
- [6x]2=6q2
- 6 36x=6q2
- q2=2x
- 2is a factor of q
- it is not a rational no.
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