How to prove geometrically that : (a+b)²=a²+2ab+b²?
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Answer:
Step 1: Draw a square ACDF with AC=a units.
Step 2: Cut AB=b units so that BC=(a−b) unts.
Step 3: Complete the squares and rectangle as shown in the diagram.
Step 4: Area of yellow square IDEO= Area of square ACDF− Area of rectangle GOFE− Area of rectangle BCIO− Area of red square ABOG
Therefore, (a−b)2=a2−b(a−b)−b(a−b)−b2
= a2−ab+b2−ab+b2−b2
= a2−2ab+b2
Hence, geometrically we proved the identity (a−b)2=a2−2ab+b
rkcomp31:
parthsail399 , ha-ha-ha,You copied wrong answer from net.I asked prove for (a+b)² and you copy pasted for (a-b)-------------------.also such solutions are useless without figure.And Do copy carefully.
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