How to prove
Lim (1-cosx)/x=0
x➡0
Answers
Answered by
1
Explanation:
1−cosx=2sin2(x2) so
1−cosxx=(x4)⎛⎜ ⎜⎝sin(x2)x2⎞⎟ ⎟⎠2 then
limx→01−cosxx≡limx→0(x4)⎛⎜ ⎜⎝sin(x2)x2⎞⎟ ⎟⎠2=0⋅1=0
1−cosx=2sin2(x2) so
1−cosxx=(x4)⎛⎜ ⎜⎝sin(x2)x2⎞⎟ ⎟⎠2 then
limx→01−cosxx≡limx→0(x4)⎛⎜ ⎜⎝sin(x2)x2⎞⎟ ⎟⎠2=0⋅1=0
Answered by
0
Answer:
Step-by-step explanation:
If we apply limit directly then we get indeterminate form
So differentiate numerator as well as denominator
lim(x->0) (0+sinx)/1
lim(x->0) sinx
apply limt now
sin0=0=rhs
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