Question

How to prove S is equal to UT plus half at square​

Answer 1

Distance travelled = Area under the line

= ut + ½ (v-u)t

Acceleration (a) = (v-u)/t and so (v-u) = at

Therefore,

Distance travelled (s) = ut + ½ (v-u)t = ut + ½ (at)t = ut + ½ at²

s=ut + ½ at²

Thus,proved.

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Answer 2

Answer s = ut + 1\2 at^2

Step-by-step explanation:

1. we know that average velocity =(v+u \2)

• total distance = average velocity ×time
• s=(v+u \2)t

• v =u+at
• we put from first equation of motion
• s=(u+at+u \2) t
• s= (2u +at \2) t
• s = (u +1\2 at)t       .at divide upon 2 = 1\2ut
• s = ut + 1\2at^2      

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