Question

how to prove (sec a+ cos a) *(sec a - cos a) = tan²a+sin²a

Answer 1

HOPE !THIS WILL HLP U

Answer 2

Step-by-step explanation: Simplifying LHS

(Sec a + cos a)*(Sec a - cos a)

(1/cos a + cos a)*(1/cos a - cos a)

(Cos^2 a +1)/cos a *(1-cos^2 a)/cos

(Cos^2 a +1)/cos a*(sin^2 a)/cos a

(Cos ^2 a sin^2 a + sin^2 a)/cos^2 a

(Cos^2 a sin^2 a)/cos^2 a + (Sin^2 a)/cos^2 a

Sin^2 a + tan^2 a