Question

how to prove sin 60 degree geometrically​

Answer 1

hope this helps you.....

Answer 2

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Consider a triangle ABC as an equilateral triangle where AB = BC = AC = 2a

Therefore, all the angle measure 60°.

Now, Draw AD perpendicular bisector to BC.

Therefore,

BD = DC = a.

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$\underline{\mathfrak{\huge{Thank\:You.}}}$