how to prove tanA/secA-1+tanA/secA+1=2cosecA
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Hello guys Namaste,
LHS=TanA\secA-1+tanA\secA+1 =tanA(secA+1)+tanA(secA-1)\(secA-1)(secA+1) =tanA[secA+1+secA-1]\sec^2 - 1 =tanA(2secA)\tan^2A (sec^2A - 1=tan^2 A) =2secA \tanA =2cosecA
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