How to prove that each angle of a rectangle is 90 degree
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Answered by
7
Given : A rectangle ABCD
to prove : angle A =
angle B =
angle C =
angle D = 90 degree
proof :
we know that
rectangle is a parallelogram where one angle is 90 degree.
hence; lets assume
angle A = 90 degree
Now
AB || BC
( opposite sides of parallelogram are parallel)
and AB is a transversal
So, angle A+ angle B = 180 degree
( interior angle on the same side of transversal are supplementary)
I hope it's help you.....
thx ✌
to prove : angle A =
angle B =
angle C =
angle D = 90 degree
proof :
we know that
rectangle is a parallelogram where one angle is 90 degree.
hence; lets assume
angle A = 90 degree
Now
AB || BC
( opposite sides of parallelogram are parallel)
and AB is a transversal
So, angle A+ angle B = 180 degree
( interior angle on the same side of transversal are supplementary)
I hope it's help you.....
thx ✌
eshasisodiya57:
8th standard
Answered by
2
Opposite sides are parallel and it has at least 1 90 degree angle (A right paralleogram)
It has 3 90 degree angles - then the fourth one must also be 90 degrees and it would then be a rectangle
Diagonals of a parallelogram are congruent
It’s a cyclic quadrilateral (It can be inscribed in a circle) and has at least 2 right angles that aren’t opposite another
Opposite sides (1 pair is enough) are equal length and it has at least 1 right angle
It has 3 90 degree angles - then the fourth one must also be 90 degrees and it would then be a rectangle
Diagonals of a parallelogram are congruent
It’s a cyclic quadrilateral (It can be inscribed in a circle) and has at least 2 right angles that aren’t opposite another
Opposite sides (1 pair is enough) are equal length and it has at least 1 right angle
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