Question

how to prove that root under 2 is a irrational number?
plz answer

Answer 1

Let us assume that √2 is rational.

Now, √2=p/q

2=p^2/q^2 (squaring)

p^2=2q^2

Therefore, p is divisible by 2.

p^2=2m

p^2=4q^2(m=2q)

Therefore, q is also divisive by 2.

But p and q are co primes.

Therefore, our assumption is wrong.

Hence, √2 is irrational.

Please mark it as brainliest question.