Question

How to prove that tan47/cot43=1

Answer 1

tan47 /(tan90-43)=1
tqn47/tan47=1
1=1

Answer 2

$\: \: \: \: \frac{ \tan(47) }{ \cot(43) } \\ = \frac{ \tan(47) }{ \cot(90 - 47) } \\ = \frac{ \tan(47) }{ \tan(47) } \\ = 1.$
Hence,
Proved.






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