Question

How to prove that the diagonals of a rectangle does not bisect each other at 90 degree please answer along with prove as attached file​

Answer 1

by

the

property

of

rectangle

Answer 2

Step-by-step explanation:

Let OABC is a rectangle and O(0,0),A(a,0),B(a,b) and C(0,6)

Let diagonal OB and AC bisects each other at point P.

Co-ordinate of midpoint P of diagonal

OB=(2(0+a),2(0+b)) 

=(2a,2b) 

Co-ordinate of mid point of P diagonal 

AC=(2(a+0),2(0+b)) 

=(2a,2b) 

Clearly diagonal rectangle bisects each other at point P.

again, OB=(a−0)2+(b−0)2 

=a2+b2 

and AC=(0−a)2+(b−0)2 

Clearly OB=AC

Hence length of diagonals of rectangle are equal