How to prove that the line joining the centres of two intersecting circles perpendicularly bisects the common chord?
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see the image for the ans
sorry a little thing is missing, after that solution, m(AMO)=m(BMO) (CPCT)
and m(AMO)+m(BMO)=180°(linear pair)
so, m(AMO) =m(BMO)= 90°
sorry a little thing is missing, after that solution, m(AMO)=m(BMO) (CPCT)
and m(AMO)+m(BMO)=180°(linear pair)
so, m(AMO) =m(BMO)= 90°
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