Question

how to prove that there is no irrational number whose square is 6?

Answer 1

HELLO.......FRIEND!!

THE ANSWER IS HERE,

There is an irrational number, whose square is 6.

The number is ,

$= > \: \sqrt{6}$

Square of the irrational number is

$= > \:( { \sqrt{6} )}^{2}$

=> 6.

So, There is an irrational number whose square is 6.


:-)Hope it helps u.

Answer 2

Hi Friend !!!

Here is ur answer ...,,

Let the number be x whose square is 6

x² = 6

x = ±√6


So there are two numbers whose square is six

The answers are

√6 and -√6



Hope it helps u : )