how to rationalize the denominator
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Hey there !!
1 / (3 – 2√2)
=> 1 / (3 – 2√2) × (3 + 2√2) / (3 + 2√2)
=> (3 + 2√2) / [ (3)² – (2√2)² ]
=> (3 + 2√2) / (9 – 8)
=> 3 + 2√2
1 / (3 – 2√2)
=> 1 / (3 – 2√2) × (3 + 2√2) / (3 + 2√2)
=> (3 + 2√2) / [ (3)² – (2√2)² ]
=> (3 + 2√2) / (9 – 8)
=> 3 + 2√2
Siddhartsid:
Thanks bro
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Hope it helps u !!!......
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