Question

how to rationalize the denominator

Answer 1

hii there here is ur solution..
=1÷3-2√2
=(1÷3-2√2) (3+2√2÷3+2√2)
=3+2√2÷(3^2-2√2^2)
=3+2√2÷9-8
=3+2√2÷1
=3+2√2 ans.

i hope it help u.....

Answer 2

$<b><u><i>$Rationalizing the denominator :

$= > \frac{1}{3 - 2 \sqrt{2} } \\ \\ = > \frac{1}{3 - 2 \sqrt{2} } \times \frac{3 + 2 \sqrt{2} }{3 + 2 \sqrt{2} } \\ \\ = > \frac{3 + 2 \sqrt{2} }{ {(3)}^{2} - {(2 \sqrt{2} )}^{2} } \\ \\ = > \frac{3 + 2 \sqrt{2} }{9 - 8} \\ \\ = > \frac{3 + 2 \sqrt{2} }{1} \\ \\ = > 3 + 2 \sqrt{2}$

=> Multiply the given numerator and denominator with the term which makes it rational.

=> Here, it is 3 + 2√2

=> in this kinda problems, you just need to change the sign and multiply it with the numerator and denominator, as shown in the solution.