Question

How to redraw this combination of resistors? please anyone explain fast.

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Answer 1

starting from the left see that 3 and 3 are in series so both together will give resistance of 6.

now this 6 is in parallel with 6 of AE.

both this six will give equivalent of 3.

now AE has 3 and DE has 3 , both are in series so will combinely give resistance of 6.

now this 6 and the 6 of AD are in parallel.

so equivalent comes to be 3 between AD.

you can solve this similarly.

you will end up with 3 inAC , 3 in BC and 3 in AB

AC and BC are in series so 3+3 =6

this 6 is in parallel with the 3 of AB.

hence equivalent resistance is 2 ohm.