Question

How to represent 729 as a sum of consecutive odd numbers?

Answer 1

let the consecutive odd numbers=(n+1)+(n+3)
sum of the consecutive odd numbers =729

so,2n+4=729
2n = 725

Answer 2

1+ 3+5+7+9+11+13+15+17+19+21+23+25+27+29+31+33+35+37+39+41+43+45+47+49+51+53 = 729