how to represent irrational number on a number line using pythagorean triplet
root 7
root 11
root 17
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Step-by-step explanation:
for root 7, construct root 5 then with help of it do root 6.
then (root6)^2 + 1^2 = root 7
for root 11, construct root 10 by 3^2+1^2 and then do root 10 sqr +1^2
for root 17, do 4^2 +1^2 =17
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