how to represent root 6 on a number line
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Hey There,
First, Find the constituents of root 6 (i.e. Root 2 x root 3).
Now on a number line take 3 units.
Then take 2 units perpendicular to the 3 units.
Now draw a straight line joining the hypotenuse at o to the perpendicular.
Now, according to Pythagoras Theorem,
(hypotenuse) ^ 2 = (2) ^ 2 x (3) ^ 2
(hypotenuse) ^ 2 = 4 x 9
(hypotenuse) ^ 2 = 36
Hypotenuse = root 36 = 6
Now, using a compass, and hypotenuse as the radius and o as the center, draw an arc cutting the positive edge of the number line.
The point cutting the number line is root 6.
Hope you get the answer.
If you like it, mark as brainliest.
First, Find the constituents of root 6 (i.e. Root 2 x root 3).
Now on a number line take 3 units.
Then take 2 units perpendicular to the 3 units.
Now draw a straight line joining the hypotenuse at o to the perpendicular.
Now, according to Pythagoras Theorem,
(hypotenuse) ^ 2 = (2) ^ 2 x (3) ^ 2
(hypotenuse) ^ 2 = 4 x 9
(hypotenuse) ^ 2 = 36
Hypotenuse = root 36 = 6
Now, using a compass, and hypotenuse as the radius and o as the center, draw an arc cutting the positive edge of the number line.
The point cutting the number line is root 6.
Hope you get the answer.
If you like it, mark as brainliest.
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