how to represent square root of 5 on number line
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8
first u draw a number line
then draw a line between 0 and 2( 2 unit)
then draw 3 perpendicular line from the point 2
then take 3 cm on compuss and draw a arch to the perpendicular line
joint this line
u will get a right-angled triangle
then
3²-2²=5
so the perpendicular line=√5
again take ur compass and draw it on ur number line.it will be √5
see attached file
then draw a line between 0 and 2( 2 unit)
then draw 3 perpendicular line from the point 2
then take 3 cm on compuss and draw a arch to the perpendicular line
joint this line
u will get a right-angled triangle
then
3²-2²=5
so the perpendicular line=√5
again take ur compass and draw it on ur number line.it will be √5
see attached file
Attachments:
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any doubt..comment here
Answered by
3
1] Draw number line and take a point O representing O on it.
Take a point A on the number line such that OA = 1(units)
2] Take a point B on the number line such that AB = 2(units)
3] With centre B draw a right angled triangle ABC(right angled at A) such that AB =2 and BC =1
4] With A as centre and radius AC draw an arch that cuts the number line at P
5] Then, AB = AP = √5
6] OC =OA+AP=1+√5.
Take a point A on the number line such that OA = 1(units)
2] Take a point B on the number line such that AB = 2(units)
3] With centre B draw a right angled triangle ABC(right angled at A) such that AB =2 and BC =1
4] With A as centre and radius AC draw an arch that cuts the number line at P
5] Then, AB = AP = √5
6] OC =OA+AP=1+√5.
Attachments:
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