Question

How to show that a distribution is t-distribution with n-1 degrees of freedom

Answer 1

Answer:

Imagine you have 4 numbers and the mean of them is 5.

Imagine you have 4 numbers and the mean of them is 5.a , b , c , d mean is 5. so you must have 4 numbers that the sum of them is equal to 20.

Imagine you have 4 numbers and the mean of them is 5.a , b , c , d mean is 5. so you must have 4 numbers that the sum of them is equal to 20.Now I want to suggest these 4 numbers freely. for the first one I say 5

Imagine you have 4 numbers and the mean of them is 5.a , b , c , d mean is 5. so you must have 4 numbers that the sum of them is equal to 20.Now I want to suggest these 4 numbers freely. for the first one I say 55 + b + c + d = 20

Imagine you have 4 numbers and the mean of them is 5.a , b , c , d mean is 5. so you must have 4 numbers that the sum of them is equal to 20.Now I want to suggest these 4 numbers freely. for the first one I say 55 + b + c + d = 20 for next number i suggest 2

Imagine you have 4 numbers and the mean of them is 5.a , b , c , d mean is 5. so you must have 4 numbers that the sum of them is equal to 20.Now I want to suggest these 4 numbers freely. for the first one I say 55 + b + c + d = 20 for next number i suggest 25 + 2 + c + d = 20

Imagine you have 4 numbers and the mean of them is 5.a , b , c , d mean is 5. so you must have 4 numbers that the sum of them is equal to 20.Now I want to suggest these 4 numbers freely. for the first one I say 55 + b + c + d = 20 for next number i suggest 25 + 2 + c + d = 20for the next number i suggest 0

Imagine you have 4 numbers and the mean of them is 5.a , b , c , d mean is 5. so you must have 4 numbers that the sum of them is equal to 20.Now I want to suggest these 4 numbers freely. for the first one I say 55 + b + c + d = 20 for next number i suggest 25 + 2 + c + d = 20for the next number i suggest 05 + 2 + 0 + d = 20

Imagine you have 4 numbers and the mean of them is 5.a , b , c , d mean is 5. so you must have 4 numbers that the sum of them is equal to 20.Now I want to suggest these 4 numbers freely. for the first one I say 55 + b + c + d = 20 for next number i suggest 25 + 2 + c + d = 20for the next number i suggest 05 + 2 + 0 + d = 20now for the fourth number (d) I have not the freedom to suggest a number anymore, because the fourth one (d) must be 13.

Imagine you have 4 numbers and the mean of them is 5.a , b , c , d mean is 5. so you must have 4 numbers that the sum of them is equal to 20.Now I want to suggest these 4 numbers freely. for the first one I say 55 + b + c + d = 20 for next number i suggest 25 + 2 + c + d = 20for the next number i suggest 05 + 2 + 0 + d = 20now for the fourth number (d) I have not the freedom to suggest a number anymore, because the fourth one (d) must be 13. so you have freedom to choose 3 of them minus 1 of them.

Imagine you have 4 numbers and the mean of them is 5.a , b , c , d mean is 5. so you must have 4 numbers that the sum of them is equal to 20.Now I want to suggest these 4 numbers freely. for the first one I say 55 + b + c + d = 20 for next number i suggest 25 + 2 + c + d = 20for the next number i suggest 05 + 2 + 0 + d = 20now for the fourth number (d) I have not the freedom to suggest a number anymore, because the fourth one (d) must be 13. so you have freedom to choose 3 of them minus 1 of them.so n-1 is the degree of freedom for measuring the mean of a sample form a population.

Explanation:

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