how to show that sum of n odd terms =n^2 correct answers please
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Answer:
Explanation:
Let S(n) = 1 + 3 + 5 + · · · + (2n − 1). We want to prove
by induction that for every positive integer n, S(n) = n2.
1. Basis Step: If n = 1 we have S(1) = 1 = 12, so the property is
true for 1.
2. Inductive Step: Assume (Induction Hypothesis) that the property is true for some positive integer n, i.e.: S(n) = n2. We must
prove that it is also true for n + 1, i.e., S(n + 1) = (n + 1)2. In
fact:
S(n + 1) = 1 + 3 + 5 + · · · + (2n + 1) = S(n) + 2n + 1 .
But by induction hypothesis, S(n) = n2, hence:
S(n + 1) = n2 + 2n + 1 = (n + 1)2
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