Question

How to simplify (12+3) (4-2) +15 (10-5) ÷3 and please explain process by process.​

Answer 1

Answer:

$\left(12+3\right)\left(4-2\right)+15\left(10-5\right)\div \:3=55$

Step-by-step explanation:

$\left(12+3\right)\left(4-2\right)+15\left(10-5\right)\div \:3$

$\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}$

$=15\left(4-2\right)+15\left(10-5\right)\div \:3$

$=15\cdot \:2+15\left(10-5\right)\div \:3$

$=15\cdot \:2+15\cdot \:5\div \:3$

$=30+15\cdot \:5\div \:3$

$=30+25$

$=55$