Math, asked by triconeinternat4664, 10 months ago

How to simplify (2a+3b+4c)(4a^2+9b^2+16c^2-6ab-12bc-8ca

Answers

Answered by dhanasekartool
13

Answer:

8a3 + 27b3 + 64c3 - 72abc

Step-by-step explanation:

 =  (2a + 3b + 4c)(4a2 + 9b2 + 16c2 - 6ab - 12bc - 8ca)

 =  (2a+3b+4c)((2a)2+(3b)2+(4c)2-(2a)(3b)-(4b)(4c)-(4c)(2a))

 =  (2a)3 + (3b)3 + (4c)3 - 3(2a)(3b)(4c)

 =  8a3 + 27b3 + 64c3 - 72abc

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