Math, asked by sid5313, 11 months ago

how to simplify (x-1)(x-2)(x-3)​

Answers

Answered by vaishnavitiwari1041
11

Answer:

Here's your answer

 {x}^{2}  - 2x - x + 2(x - 3) \\  \\  {x}^{2}  - 3x + 2(x - 3) \\  \\ x( {x}^{2}  - 3 x + 2) - 3( {x}^{2}  + 3x + 2) \\  \\  {x}^{3}  - 3 {x}^{2}  + 2x - 3 {x}^{2}  - 9x - 6 = 0 \\  \\  {x}^{3}  - 6 {x}^{2}  - 7x - 6 = 0

Hope it helps

Answered by srushtisp2020
9

x3−6x2+11x−6

Explanation:

one way is as follows

note that

(x+a)(x+b)(x+c)=x3+

(a+b+c)x2+(ab+bc+ac)x+abc

here

a=−1,b=−2and c=−3

⇒(x−1)(x−2)(x−3).=x3+(−1−2−3)x2+(2+6+3)x+(−1)(−2)(−3)

=x^3−6x^2+11x−6

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