Question

how to slove this question ​

Answer 1

Answer:

Solution:-

• x = 30° [ Vertically opposite angles ]

• z = 90° [ Given ]

• 30° + z + 3y = 180°

• 30° + 90° + 3y = 180°

• 3y = 60°

• y = 20°

The value of x y and z are 30° , 20° and 90°.

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Answer 2

$\huge\bf{\underline{\overline{\pink{Solution :}}}}$

${\leadsto{\boxed {\boxed {\purple {\mathfrak x={30}^{\circ}}}}}} \bf\longrightarrow \Big(Vertically \: Opposite \: Angle \Big)$

${\leadsto{\boxed {\boxed {\purple {\mathfrak z={90}^{\circ}}}}}} \bf\longrightarrow \Big(Vertically \: Opposite \: Angle \Big)$

$\leadsto \sf x+ 3y+ z={180}^{\circ}$

$\leadsto \sf {30}^{\circ} + 3y+{90}^{\circ} ={180}^{\circ}$

$\leadsto \sf {120}^{\circ} +3y={180}^{\circ}$

$\leadsto \sf 3y={180}^{\circ}-{120}^{\circ}$

$\leadsto \sf 3y={60}^{\circ}$

$\leadsto \sf y=\dfrac{60}{3}$

$\leadsto \sf y=\dfrac{\cancel{60}}{\cancel{3}}$

$\leadsto{\boxed {\boxed {\purple {\mathfrak y={20}^{\circ}}}}}$

${\pmb{\orange {\bf \therefore \:The\:\: values \: are}}} \begin{cases}{\pink{\bf{x={30}^{\circ}}}} \\{\pink{\bf {y={20}^{\circ}}}}\\{\pink{\bf{z={90}^{\circ}}}}\end{cases}$