Question

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Answer 1

Answer:

Which class are you studying

Answer 2

Step-by-step explanation:

we have angle BAC = 60°

angle ABC = 90°

therefore, angle BCA = 30°

By law of sins,

$\frac{ \sin(60) }{6} = \frac{ \sin(90) }{AC} \\ \frac{ \sqrt{3} }{12} = \frac{1}{AC} \\ AC = \frac{12}{ \sqrt{3} } \\ 4 \sqrt{3}$