how to solve 1 2 root3/root2
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0
Answer:
We have,
1+
2
1
+
2
+
3
1
+
3
+
5
2
=
1+
2
1
×
1−
2
1−
2
+
2
+
3
1
×
2
−
3
2
−
3
+
3
+
5
2
×
3
−
5
3
−
5
=
1−2
1−
2
+
2−3
2
−
3
+
3−5
2(
3
−
5
)
=
−1
1−
2
+
−1
2
−
3
+
−2
2(
3
−
5
)
=−1+
2
−
2
+
3
−
3
+
5
=
5
−1
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