Question

how to solve (1/3x+2/3y)^3 using identity​

Answer 1

Answer:1/27x^3 + 4/27y^3 +2/9x^2y + 4/9 xy^2

Step-by-step explanation:(a+b)^3

=a^3+b^3+3ab(a+b)

Now

(1/3x +2/3y)^3

=(1/3x)^3 + (2/3y)^3 + 3(1/3x) (2/3y) [1/3x+2/3y]

=1/27x^3 + 4/27y^3 + 6xy/9 (1/3x + 2/3y)

=1/27x^3 + 4/27y^3 + 2/9x^2y + 4/9xy^2