Question

how to solve 1=modulus of -(k+3)/1-3k​

Answer 1

Answer:

answr

search

What would you like to ask?

MATHS

Let ω be a complex number such that 2ω+1=z where z=

−3

, if

∣

∣

∣

∣

∣

∣

∣

∣

1

1

1

1

−ω

2

−1

ω

2

1

ω

2

ω

7

∣

∣

∣

∣

∣

∣

∣

∣

=3k, then k ie equal to.

Share

Study later

VIDEO EXPLANATION

ANSWER

2w+1=z

2w+1=

3

i

w=

2

−1+

3

i

⇒w

2

=

2

−1−

3

i

=−w−1

Now,

∣

∣

∣

∣

∣

∣

∣

∣

1

1

1

1

−ω

2

−1

ω

2

1

ω

2

ω

7

∣

∣

∣

∣

∣

∣

∣

∣

=3k ...Given

⇒

∣

∣

∣

∣

∣

∣

∣

∣

1

1

1

1

w

w

2

1

w

2

w

∣

∣

∣

∣

∣

∣

∣

∣

=3k

1(w

2

−w

4

)−1(w−w

2

)+1(w

2

−w)=3k

3w

2

−3w=3k

3(w

2

−w)=3k

k=w

2

−w

k=−1−2w

=−1−(−1+

3

i)

=−

3

i

=−z